24=200+4q+2q^2

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Solution for 24=200+4q+2q^2 equation: 



24=200+4q+2q^2

We move all terms to the left:

24-(200+4q+2q^2)=0

We get rid of parentheses

-2q^2-4q-200+24=0

We add all the numbers together, and all the variables

-2q^2-4q-176=0

a = -2; b = -4; c = -176;
Δ = b2-4ac
Δ = -42-4·(-2)·(-176)
Δ = -1392
Delta is less than zero, so there is no solution for the equation

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